Retired AF Guy
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Some amazing imagery of a Croatian CL-415 dropping water on a fire near Rijeka, Croatia. Originally posted on You tube in 2019.
and bird's nests.I'd be checking the underside for twigs.
Not as close as it looks, actually. The long telephoto lens foreshortens the perspective significantly.I'm not a pilot but putting that plane so close to the cliff, those guys have balls of steel!
Especially if you're an Eastern European pilot with a cigarette in one hand and a blood alcohol level near blackout...That said, there are a whole bunch of factors that make such flying very demanding and not without significant risk, and visually very impressive, for sure.
Flying out of Bull harbour in a float equipped Beaver. Goes to the end of the lagoon, powers up, goes on step, continues on step, trees at the end of the lagoon get closer, I ask on the intercomm: "Does it always take you this long to get airborne?" The Pilot; "No" , the distinct feeling of sphincter squeezing and everyone staring quietly at the trees.....I was a passenger in a float plane taking off (perhaps a tad heavy) from a small lake and we later found a twig lodged in an elevator. Good times.
Man, you probably could have just said "because of the direction of the camera and based on my experience, I believe this aircraft to be about 100 feet off the ground" and I suspect most of us would have taken that at face value...Not as close as it looks, actually. The long telephoto lens foreshortens the perspective significantly.
Let’s break down this picture (measuration techniques):
View attachment 68651
Because the plane is essentially perpendicular to the camera, the length is not distorted (like the banked wings are), so that is a good linear scale reference. So too with apparent altitude of picture elements: plane; terrain elements, etc., so a small-angle approximation at distance supports linear height comparisons as well.
So, let’s start by measuring the apparent height difference between the upper wingtip of the plane and the related upper wingtip shadow…and compare that to the aircraft length, based on both axes being linearly undistorted. I see the height difference between plane and shadow to be very similar to the length of the plane a CL-415 is 20m/66’ long, so I say the plane is vertically 20m/66’ above the shadow.
Now some assumptions about the terrain. It looks steep but we get some hints from a similarity of angle between the banked wings and the shadow of the wings on the terrain. The wing and its shadow appear to slant at the same angle (top behind the bottom, respectively) which tells me that the terrain is actually inclined at a slope similar to the bank of the wings.
A CL-415’s wingspan is 28m/92’. Comparing the wing’s apparent length visually to the plane’s length…I say the banked wings look about 3/4 (0.75) high as the plane in long, so it’s apparent height difference between upper and lower wingtip is 20m X 0.75 = 15m. Some quick trigonometry for a 15m height (upper tip above lower tip) and a 28m hypotenuse (the undistorted wingspan) sin-1(15/28) = 33° bank angle. That’s not an extreme bank angle, close to what we call a Standard Rate 2 turn (heading change of 6°/sec) although a Rate 1 Turn (3°/sec and bank angles in the 18-22° range) is what is often used in IFR flight. I’ll also interpret the ground slope to be similar, since the apparent layback of the wing shadow on the ground is close to parallel to the actual wings. If the ground was sloped much different than the banked wings, the shadow would not be so parallel to the wings…it would slant forward or aft (for steeper or shallower terrain respectively).
So, we know (well, we assume/approximate) that the terrain is similar to the wing’s bank angle at 33°…or a 63% gradient (fairly steep, definitely hiking territory), so we use that to assess the distance the aircraft is out from the terrain. We figured the aircraft was 15m higher than where it’s shadow hit the ground. Using the 63% gradient (which has a 1 unit rise over a 1.57 unit run, from gradient tables) a 15m height yields a lateral 23.5m setback of the shadow horizontally from the aircraft. Assuming the terrain is consistently sloped (definitely an assumption), to determine the aircraft’s true outset horizontally from the terrain at the SAME altitude, we consider how ouch further back the terrain sets back as we come up from the shadow’s altitude to be level with the aircraft. We use the terrain’s ‘consistent slope’ and apply the same horizontal setback from shadow back up to the plane, but rearwards up the hill, not forward through the air to the plane itself. Total horizontal separation of the plane to the ground behind it at the same altitude? 23.5m + 23.5m = 47m (155’).
So how about the vertical heigh of the plane above the ground immediately below it? We use the same theory that height down to the shadow can then continue down the same distance following the terrain down and forward to be right under the plane, so we’re going to double that to relative to the plane’s height above its shadow. 15m + 15m = 30m (99’…let’s call it 100’)
So, all things considered (and approximated) the crew is flying their plane 100’ directly about the ground, is 155’ forward of the ground at the same altitude, and the closest distance perpendicular from the ground directly to the plane is 25m (84’) (30m height X cosine33°), or slightly higher than an 8-story building.
That said, there are a whole bunch of factors that make such flying very demanding and not without significant risk, and visually very impressive, for sure.
So a birds nest from a tall tree?Not as close as it looks, actually. The long telephoto lens foreshortens the perspective significantly.
Let’s break down this picture (measuration techniques):
View attachment 68651
Because the plane is essentially perpendicular to the camera, the length is not distorted (like the banked wings are), so that is a good linear scale reference. So too with apparent altitude of picture elements: plane; terrain elements, etc., so a small-angle approximation at distance supports linear height comparisons as well.
So, let’s start by measuring the apparent height difference between the upper wingtip of the plane and the related upper wingtip shadow…and compare that to the aircraft length, based on both axes being linearly undistorted. I see the height difference between plane and shadow to be very similar to the length of the plane a CL-415 is 20m/66’ long, so I say the plane is vertically 20m/66’ above the shadow.
Now some assumptions about the terrain. It looks steep but we get some hints from a similarity of angle between the banked wings and the shadow of the wings on the terrain. The wing and its shadow appear to slant at the same angle (top behind the bottom, respectively) which tells me that the terrain is actually inclined at a slope similar to the bank of the wings.
A CL-415’s wingspan is 28m/92’. Comparing the wing’s apparent length visually to the plane’s length…I say the banked wings look about 3/4 (0.75) high as the plane in long, so it’s apparent height difference between upper and lower wingtip is 20m X 0.75 = 15m. Some quick trigonometry for a 15m height (upper tip above lower tip) and a 28m hypotenuse (the undistorted wingspan) sin-1(15/28) = 33° bank angle. That’s not an extreme bank angle, close to what we call a Standard Rate 2 turn (heading change of 6°/sec) although a Rate 1 Turn (3°/sec and bank angles in the 18-22° range) is what is often used in IFR flight. I’ll also interpret the ground slope to be similar, since the apparent layback of the wing shadow on the ground is close to parallel to the actual wings. If the ground was sloped much different than the banked wings, the shadow would not be so parallel to the wings…it would slant forward or aft (for steeper or shallower terrain respectively).
So, we know (well, we assume/approximate) that the terrain is similar to the wing’s bank angle at 33°…or a 63% gradient (fairly steep, definitely hiking territory), so we use that to assess the distance the aircraft is out from the terrain. We figured the aircraft was 15m higher than where it’s shadow hit the ground. Using the 63% gradient (which has a 1 unit rise over a 1.57 unit run, from gradient tables) a 15m height yields a lateral 23.5m setback of the shadow horizontally from the aircraft. Assuming the terrain is consistently sloped (definitely an assumption), to determine the aircraft’s true outset horizontally from the terrain at the SAME altitude, we consider how ouch further back the terrain sets back as we come up from the shadow’s altitude to be level with the aircraft. We use the terrain’s ‘consistent slope’ and apply the same horizontal setback from shadow back up to the plane, but rearwards up the hill, not forward through the air to the plane itself. Total horizontal separation of the plane to the ground behind it at the same altitude? 23.5m + 23.5m = 47m (155’).
So how about the vertical heigh of the plane above the ground immediately below it? We use the same theory that height down to the shadow can then continue down the same distance following the terrain down and forward to be right under the plane, so we’re going to double that to relative to the plane’s height above its shadow. 15m + 15m = 30m (99’…let’s call it 100’)
So, all things considered (and approximated) the crew is flying their plane 100’ directly about the ground, is 155’ forward of the ground at the same altitude, and the closest distance perpendicular from the ground directly to the plane is 25m (84’) (30m height X cosine33°), or slightly higher than an 8-story building.
That said, there are a whole bunch of factors that make such flying very demanding and not without significant risk, and visually very impressive, for sure.
Man, you probably could have just said "because of the direction of the camera and based on my experience, I believe this aircraft to be about 100 feet off the ground" and I suspect most of us would have taken that at face value...
Thanks for the explanation though, that was interesting to work my way through.
Not as close as it looks, actually. The long telephoto lens foreshortens the perspective significantly.
So, all things considered (and approximated) the crew is flying their plane 100’ directly about the ground, is 155’ forward of the ground at the same altitude, and the closest distance perpendicular from the ground directly to the plane is 25m (84’) (30m height X cosine33°), or slightly higher than an 8-story building.
That said, there are a whole bunch of factors that make such flying very demanding and not without significant risk, and visually very impressive, for sure.
Dana381, definitely something to think about, and your methodology is exactly the math to consider! It’s also why ASW aircraft at low altitude have to be careful when they crank and bank since a P-3/P-8 have a decent sized wingspan. Same applies for helicopters. Imagine flying a Chinook at the same speed that CL-415 is flying, but wheels just 3m/10’ over the ground and a rotor span of 18m/60’…three times wider on either side of the fuselage than the height of the wheels over the ground…definitely have to be careful banking at those low altitudes!
Or the oft-seen doing laps around a lake trying to get up speed, sometimes getting one pontoon out of the water to reduce drag. A 185 on floats has limited money-making capacity. Bush pilots are a different breed.Flying out of Bull harbour in a float equipped Beaver. Goes to the end of the lagoon, powers up, goes on step, continues on step, trees at the end of the lagoon get closer, I ask on the intercomm: "Does it always take you this long to get airborne?" The Pilot; "No" , the distinct feeling of sphincter squeezing and everyone staring quietly at the trees.....